a very quick Riddle | Xi'an's Og

a very quick Riddle

A very quick Riddler’s riddle last week with the question

Find the (integer) fraction with the smallest (integer) denominator strictly located between 1/2020 and 1/2019.

and the brute force resolution

for (t in (2020*2019):2021){ 
   a=ceiling(t/2020)
   if (a*2019<t) sol=c(a,t)}

leading to 2/4039 as the target. Note that

$\dfrac{2}{4039}=\dfrac{1}{\dfrac{2020+2019}{2}}$

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This entry was posted on January 22, 2020 at 12:19 am and is filed under Books, Kids, pictures, R with tags Egyptian fractions, Gros-Horloge, jatp, Normandie, riddle, Rouen, The Riddler. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

4 Responses to “a very quick Riddle”

cellocgw Says:
January 23, 2020 at 2:07 pm

I see (at Riddler page) that solution by way of continued fractions is recommended.

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a very quick Riddle | R-bloggers Says:
January 23, 2020 at 8:13 am

[…] article was first published on R – Xi'an's Og, and kindly contributed to R-bloggers]. (You can report issue about the content on this page here) […]

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a very quick Riddle - Think Unparallel. Says:
January 22, 2020 at 1:05 pm

[…] article was first published on R – Xi’an’s Og, and kindly contributed to R-bloggers]. (You can report issue about the content on this page […]

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a very quick Riddle – Data Science Austria Says:
January 22, 2020 at 10:04 am

[…] by data_admin [This article was first published on R – Xi’an’s Og, and kindly contributed to R-bloggers]. (You can report issue about the content on this page […]

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